Decrypting Malicious PDF Documents Part Two Synack dumps with pin 2017, cvv shop pro

Patrick Wardle, Director of Synack Research
This is the second blog post in a two-part series discussing how to decrypt PDF documents for analytical purposes. Click here for part one.
Guess, what? “it’s hammer, decryption time!” Section 7.6.2 of [5], verbosely describes the encryption algorithm for protecting PDF documents. Since the PDF specified AES, a symmetric cryptographic algorithm, with knowledge of the encryption key the same sequence of steps can performed to decrypt the document. Instead of simply regurgitating the mind-numbing content of the PDF encryption specification, it seemed more productive to instead illustrate the decryption of a PDF document step-by-step in a programmatic manner. Of course, if a step is unclear, or more details are desired, feel free to consult the official documentation from Adobe (we won’t judge).
The first step in decrypting a PDF document is to generate what Adobe calls the ‘file key.’ To generate this key, four pieces of information are required; the file ID, the owner password hash, the user password, and the document’s permissions flag. Of course, if the user password is not blank, the PDF cannot be decrypted (discounting brute-force/cryptanalysis attacks).
The file ID is stored in the PDF documents’s trailer (see figure 0x1). Specifically, it is first value of the /ID object. For the PDF document referenced in this blog (encrypted.pdf), the full ID is:
[], meaning the file ID is simply: F247C9CF56A1484FB2C4F8C200FA269F.
Given a helper function (GetValueForKey()) that can extract an initial value  from a key, the following code will extract the file ID:
The next piece of information required for generating the file key, is the owner password hash, stored within the PDF encryption object. This value, accessed via the ‘/O’ key, should be extracted and converted into 32 bytes of binary data. This extraction is a touch tricky, as the password hash is stored as an ascii string containing escaped values that must be manually unescaped or converted [3]. For example, a ‘r’ is stored in two characters (ascii ‘’, hex 0x5c and ascii ‘r’, hex 0x72). This two byte value must be converted into the single byte new line character (hex 0x0d).
For following code illustrates one way to achieve the correct extraction of  the owner’s password:
When the code in figure 4 is run on the encrypted.pdf document, it produces,  hash is: 0x30e714592e1ff1fe285a601b413c71caf3b989576b72ac51371cf782a7f32f0b
Assuming that the user’s password is blank, the final piece of required information for generating the file key, is the value of the permissions flag (under the ‘/P’ key) also found within the PDF’s encryption object. Though stored as string representation of a signed integer (e.g., -3392), it must be  extracted as unsigned 32bit integer:
With all three (again, ignoring the user password as its assumed to be blank), pieces of required information, the file key can now be generated. The key generation algorithm is described in Adobe’s documents, under the section ‘Computing an Encryption Key’ on page 18 [8]. In short the user’s password is padded up to 32 bytes, with a known/static password pad, then hashed with the owner password, the value permissions flag, and the file ID. This hash is then re-hashed 50 times. Since the user’s password is blank, all 32 bytes of the password pad are fully used. With a known password pad, an  encrypted PDF document (with a blank password) can be fully decrypted.
Adobe describes a way to validate that the computed key is in fact correct. That is to say, it will successfully decrypt the PDF document. In short, the user’s password (again padded to 32 bytes with the password pad), and the PDF’s file ID are hashed. The resulting digest, is first decrypted with RC4 using the generated file key as the decryption key. The decrypted data is then decrypted 19 more times, with a decryption key generated by XOR’ing the decryption count (0 thru 18), with each byte of the computed file key. The final result of this hash/decryption loop should match the last 16 bytes of user’s password hash in the PDF’s encryption object.
This algorithm is of course much easier to understand in code:
Then, a stream that contains exploit-related javascript:
[1] Acrobat Reader Vulnerabilities
[2] Pdf Current Threats
[3] Analysing (sic) Encrypted PDF Files for Malware
[4] PDF encryption, using Adobe’s “Standard Security Handler”
[5] Document management — Portable document format — Part 1: PDF 1.7
[6] Anatomy of Malicious PDF Documents
[7] Didier Stevens
[8] Adobe® Supplement to the ISO 32000
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